Function interface has an abstract method "apply" which take argument of type T and must returns a result of type R.
Java definition
Represents a function that accepts one argument and produces a result.
public interface Function<T, R> {
R apply(T t);
...
}
Here are some test cases.
Applies this function to the given argument.
@Test
public void testFuncApply()
{
Function<Integer, Integer> sqrt = (num) -> num * num;
Assertions.assertEquals(Integer.valueOf(100), sqrt.apply(10));
}
A composed function that first applies the function to its input, and then applies this to the result.
@Test
public void testFuncCompose()
{
//given
Function<Integer, Integer> sqrt = (num) -> num * num;
Function<String, Integer> input = sqrt.compose(((s) -> Integer.parseInt(s)));
//when
Integer result = input.apply("9");
//verify
Assertions.assertEquals(Integer.valueOf(81), result);
}
A composed function that first applies this function to its input and the applies the function to the result.
public void testFuncAndThen()
{
//given
Function<Integer, Integer> sqrt = (num) -> num * num;
Function<Integer, Integer> times = sqrt.andThen((num) -> num * num);
Function<String, Integer> input = times.compose(((s) -> Integer.parseInt(s)));
//when
Integer result = input.apply("10");
//verify
Assertions.assertEquals(Integer.valueOf(10000), result);
}
A function that always returns its input argument.
@Test
public void testIdentity()
{
//given
Map<String, String> result =
Arrays.asList("a", "b", "c")
.stream()
.collect(Collectors.toMap(Function.identity(), str -> str));
//verify
Assertions.assertTrue(result.size() == 3);
Assertions.assertEquals(result.get("a"), "a");
Assertions.assertEquals(result.get("b"), "b");
Assertions.assertEquals(result.get("c"), "c");
}
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